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 Mathematics 141 Practice quiz 4factoring When you are sure of your answers, send them to your Professor: Enter your name above Enter preferred email address above Enter student I.D. above
[1] Factor 5355 completely :

 (a) (5)(5)(3)(3)(13) (b) (5)(7)(9)(17) (c) (5)(63)(17) (d) (5)(3)(3)(7)(17) (e) none of the above

[2] Factor the following completely : 33x3y3 + 21x2y5

 (a) 3x2y3(11x + 7y2) (b) 3x2y3(11x + 21y2) (c) 33x3y3(1 + 21x2y5) (d) (33x3y3 + 1)(21x2y5) (e) (33)(21)x2y3(x + y2) (f) none of the above

[3] Factor the following completely : 27x2 - 12y4

 (a) 3(9x2 - 4y4) (b) 33x2 - 22(3)y4 (c) 3(3x - 2y)(3x + 2y) (d) 3(3x - 2y)2 (e) (27 - 12)(x2 - y4) (f) none of the above
[4] Factor the following completely : 54x3y6 - 16z9

 (a) 54(xy2)3 - 16(x3)3 (b) 2(27x3y6 - 8z9) (c) (2x2 - z9)(27y6 + 16) (d) 2(3xy2 - 2z3)(9x2y4+ 6xy2z3 + 4z6) (e) 2(3xy2 - 2z3)3 (f) none of the above
[5] Enter the two factors in the spaces provided :

 2x2 - 3x - 2 = ( )( )
[6] Enter the two factors in the spaces provided :

 9x2y2 - 121 = ( )( )
[7] Enter the two factors in the spaces provided :

 9x2y2 - 12xy + 4 = ( )( )
[8] Enter the two factors in the spaces provided :

 9x2 - 3x - 3xy + y = ( )( )
[9]
 Laura's dorm room is a rectangle 2 feet longer than wide, and has a floor area of 195 square feet. How long is Laura's room?
Which of the following defines a variable and an equation correctly translating the boxed problem above?

 (a) Let x = Laura's dorm room ; x(x - 2) = 195 (b) Let x = the area of Laura's dorm room ; x(x + 2) = 195 (c) Let x = the length of Laura's dorm room ; x(x + 2) = 195 (d) Let x = the length of Laura's dorm room ; x(x - 2) = 195 (e) Let x = the width of Laura's dorm room ; x(x - 2) = 195 (f) Let x = the area of Laura's dorm room ; x(x - 2) = 195 (g) none of the above
[10]
 The perimeter of a rectangular field is 68 meters, and its diagonal measures 26 feet. What are the dimensions of the field?
Which of the following defines a variable and an equation correctly translating the boxed problem above?

 (a) Let x = the length of the field ; x2 + (34 - x)2 = 262 (b) Let x = the dimensions of the field ; x2 + (68 - x)2 = 262 (c) Let x = the width of the field ; x2 + (68 - 2x)2 = 262 (d) Let x = the dimensions of the field ; x2 + (34 - x)2 = 262 (e) Let x = the length of the field ; 2x + 2(26 - x)2 = 68 (f) Let x = the perimeter of the field ; x2 + (68 - 2x)2 = 262 (g) none of the above

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