To factor x^{6} + 22x^{3} + 121 ,
use the formula a^{2} + 2ab + b^{2} = (a + b)^{2},
noting that here, the acting variable is " x^{3} " rather than "x". Thus,
"a" is " x^{3} " and "b" is "11", to get:
x^{6} + 22x^{3} + 121 = (x^{3} + 11)^{2}.

No more factoring is possible.

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