To factor 125x^{3} + 64 ,
use the form a^{3} + b^{3} = (a + b)(a^{2} - ab + b^{2}),
where here "a" is "5x" and "b" is "4", to get:
125x^{3} + 64 = (5x + 4)[(5x)^{2} - (5x)(4) + 4^{2}]
125x^{3} + 64 = (5x + 4)(25x^{2} - 20x + 16).

No more factoring is possible.

To return to factoring self-test, hit the "BACK" button (upper left)