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Given Events E1 and F, write two conditional probabilities :
P(E1 | F) = |
P(E1 ![]() ![]() P(F) |
or |
P(E1 ![]() |
P(E1 | F)![]() |
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P(F | E1) = |
P(E1 ![]() ![]() P(E1) |
or |
P(E1 ![]() |
P(F | E1)![]() |
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P(E1 | F)P(F) = P(F | E1)
P(E1)
Divide both sides of the above by P(F) , to get a SIMPLE FORM OF BAYES RULE : |
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The denominator P(F) above can be re-written if the sample space (and hence F) are partitioned, or divided, into 2 or more non-overlapping pieces, as implied in the classic box-cutting magic trick, and its representation using sets in the figures (right) : | ![]() |
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If E1 , E2 , and E3 do not overlap, then
(F E1) ,
(F
E2) , and
(F
E3) also do not overlap, and hence
P(F) =
P(F E1) +
P(F
E2) +
P(F
E3) ;
re-writing each term as a product (as at the top of this page) :
P(F) =
P(E1)P(F | E1) +
P(E2)
P(F | E2) +
P(E3)
P(F | E3) ;
We can then re-write the simpler form (above) to a LARGER FORM OF BAYES RULE :
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