Let n=number of entrees on the menu
A "family dinner" is an
un-ordered
4-entree subset of the set of n entrees on the menu
;
thus
:
C(n,4) =
n
!
4
!
x (n-4)
!
is the number
of possible
dinners
Using the above formula for various n
:
C(4,4)
= 1
C(5,4)
= 5
C(6,4)
= 15
C(7,4)
= 35
C(8,4)
= 70
C(9,4)
= 126
C(10,4)
= 210
C(11,4)
= 330
see final solution and sample calculation?