One simple example of Gauss/Jordan
appears with our list of row operations. |
Below is a system
of equations which
we will solve
using G/J |
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Below is the
1st augmented
matrix: Note the
location of the
red-circled "1" in I3
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Row
operations
named below
change column 1
into what we want |
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Next we change "5"
in the 2-2 position
encircled below.
This is where "1"
in I3 must be |
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Below is the result of
"R2 = (1/5)r2". The
element in the 2-2 position
has become "1" as in I3 |
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Row operations
to change the rest
of column 2 are below |
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Column 2 below is now
what it is in I3.
Now alter the "7"
encircled in red |
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Using the row op
"R3 = (-1/ 7)r3"
below to change
"-7" to "1" as in I3 |
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Below is the result of
"R3 = (-1/ 7)r3".
Now we must change
the rest of column 3 |
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Row operations
to change the
rest of column 3 are below |
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The result of all
row operations
is below, with
the identity I3
matrix in blue |
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Re-writing the
final matrix as
equations gives
the solution to
the original system |
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This page last updated 22 July 1999 |
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