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EXAMPLE OF SIMPLEX PROCEDURE
FOR A NON-STANDARD
LINEAR PROGRAMMING PROBLEM |
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Below is
original
Problem |
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Red symbols
below were
changed by
step NS-1 |
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Red variables sn
below are called
SLACK VARIABLES |
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There is a tie
for most negative
right-hand number.
Either "-12" is OK |
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In the matrix
below, the
pivot has
become "1" |
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Named below are the 4
row operations needed
to pivot on the number
"-2" encircled in red |
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Row operations
are named above;
their results
are below |
Highlighted
is the
new ISM |
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In the matrix
below, the
pivot has
become "1" |
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Named below are the 4
row operations needed
to pivot on the number
"-3/2" encircled in red |
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Row operations are named above; their
results are at the right. The new ISM is highlighted. All right-most numbers above the
bottom (objective) row are now zero or bigger;
Phase I is now ended.
Phase II now begins, presented as "Step 8" in Rolf (Pg 323) |
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In many non-standard problems, we would now find a negative indicator in
the bottom row. However, in our last tableau above, a nice coincidence finds
all indicators (0, 0, 0, 4/3, 1/3) are zero or bigger; "-20" is not an
indicator. Hence, Phase II is completed at it's start, because the above tableau is a
final tableau, and the row operations of SIMPLEX are done!
To obtain the final basic solution to our problem,
1st set equal to 0 each variable NOT associated
with the highlighted ISM: variable tags are placed
above each column in the final tableau.
2nd
convert each row of the final tableau back
into it's equation format, as at the right, to find the
values of the remaining variables (shown in red). |
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