The above information is from your computer : be sure it is correct.
For grade credit, submit over the internet by 11:59 PM (= 23:59 hours) on Sunday 14 February 2016 |
For the following 3 questions [4][5][6], you must name the formula you plan
to use (for 3 points), and then enter the
answer to the question (for 2 added points).
On paper tests, these instructions will be
somewhat different. See an example ?. |
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Your available choices of formulas (not given on original test) are: |
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Formula #1 |
Formula #2 |
Formula #3 |
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Failure to practice this kind of problem accounted for
more lost points than any other problem type on this test |
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Scoring : Formula worth 3 pts ; numerical answer worth an added 2 pts (zero pts if formula is wrong) |
[4] |
Bart is about to receive money in a trust started by a royal relative 21 years
ago (at Bart's birth). If $2100 was originally placed in this trust, how much
will Bart receive today, if the trust has earned 8% per year
compounded quarterly? (See instructions above) |
[5] |
The Taylors have a 30-year home mortgage to secure a home loan
of $100 000. If annual interest rates are 6% compounded
monthly, what is the Taylors' monthly mortgage payment? |
[6] |
For the past 12 years, Julie's employer has contributed $1OO at the
end of each month into a retirement account paying interest at an
annual rate of 6% compounded monthly. How much is in Julie's account
now? |
[7] |
(a)(2 pts) Write as a single matrix : [Original matrices had a 3rd row ] |
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(b)(3 pts) Find this matrix product : |
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[8] |
Use GAUSS/JORDAN method to solve the system below left,
clearly writing all row operations BETWEEN the affected
matrices, and using the format
rn + k . rm = Rn
or
k . rn = Rn
to name the row operations, where Rn is the name of the (new) row being built,
and rn or rm are the name(s) of rows in the
(old) existing matrix. Note that this naming
scheme is the one used in examples done during class. If your work is
correct, your matrices will contain NO fractions; each step of your work should look as below right : |
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x |
- |
2y |
+ |
z |
= |
6 |
2x |
+ |
y |
- |
3z |
= |
-3 |
x |
- |
3y |
+ |
3z |
= |
10 |
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[9] |
(a)(3 pts)
Find A-1 for the matrix A below, using row
operations. Name each row operation as described in [8]
above. You will encounter a few fractions with
denominator of "7" but no other fractions. Answer is
given, so credit is only for WORK. |
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A = |
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and your answer will be |
A-1 = |
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All 8 boxes must be correct for 2 pts (no partial credit) |
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(c) |
(zero pts) On classroom
tests the student must also find the solution
to the system in [9](b) above by calculating
X = A-1.B,
using the matrices A-1 and B from [9](a) and
[9](b). This skill is not tested here. |
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